```2
x1**3+x1*x2;
x2**2+x2;

TITLE : decker1, with three regular roots and one triple root

The system has three regular roots and the origin is a triple root
for which two deflations are needed.

REFERENCES :

D.W. Decker, C.T. Kelley:
"Newton's method at singular points. II"
SIAM J. Numer. Anal. 17, 465-471, 1980

THE SOLUTIONS :
6 2
===========================================================
solution 1 :
t :  1.00000000000000E+00   0.00000000000000E+00
m : 1
the solution for t :
x1 : -1.00000000000000E+00   0.00000000000000E+00
x2 : -1.00000000000000E+00   0.00000000000000E+00
== err :  0.000E+00 = rco :  4.000E-01 = res :  0.000E+00 ==
solution 2 :
t :  1.00000000000000E+00   0.00000000000000E+00
m : 1
the solution for t :
x1 : -4.68237338654844E-06   7.84924377521673E-06
x2 :  0.00000000000000E+00   0.00000000000000E+00
== err :  6.266E-06 = rco :  3.396E-10 = res :  7.955E-16 ==
solution 3 :
t :  1.00000000000000E+00   0.00000000000000E+00
m : 1
the solution for t :
x1 :  0.00000000000000E+00   0.00000000000000E+00
x2 : -1.00000000000000E+00   0.00000000000000E+00
== err :  0.000E+00 = rco :  1.000E+00 = res :  0.000E+00 ==
solution 4 :
t :  1.00000000000000E+00   0.00000000000000E+00
m : 1
the solution for t :
x1 : -2.95529258749206E-06  -5.31655257281928E-06
x2 :  0.00000000000000E+00   0.00000000000000E+00
== err :  4.136E-06 = rco :  1.529E-10 = res :  2.358E-16 ==
solution 5 :
t :  1.00000000000000E+00   0.00000000000000E+00
m : 1
the solution for t :
x1 :  1.00000000000000E+00   0.00000000000000E+00
x2 : -1.00000000000000E+00   0.00000000000000E+00
== err :  0.000E+00 = rco :  4.000E-01 = res :  0.000E+00 ==
solution 6 :
t :  1.00000000000000E+00   0.00000000000000E+00
m : 1
the solution for t :
x1 :  9.11529253275207E-06   1.25430449151191E-07
x2 :  0.00000000000000E+00   0.00000000000000E+00
== err :  4.620E-06 = rco :  2.561E-10 = res :  7.882E-16 ==
```