h[0] = 1, h[1] = 0, and h[n] = -2*(n-1)*h[n-2].
Answer:
+------------------+
| L = [1,0]; n = 2 |
+------------------+
|
+------> \|/
| ^^^^^^^^
| / \
| / n < 100? \ no +-----------+
| \ / ------> | print L |
| \--------/ +-----------+
| |
| | yes
| \|/
| +---------------------------+
| | L.append(-2*(n-1)*L[n-2]) |
| +---------------------------+
| |
| \|/
| +-------------+
| | n = n + 1 |
| +-------------+
| |
| \|/
| |
+-----------------+
Answer:
L = [1,0]
for n in range(2,100):
L.append(-2*(n-1)*L[n-2])
print L # optional