Exercise 4.1: Verify Gauss relation:
n-1
--- a
\ ak { n if w = 1
/ w = {
--- { 0 otherwise
k=0
Let z be the sum at the left of the equation above
and we derive
n-1 n n-1
--- --- ---
a \ (a+1)k \ ak \ ak na
w z = / w = / w = / w + w
--- --- ---
k=0 k=1 k=1
Since w is a root of unity, we have w^n = 1, and thus
also w^(na) = 1 = w^(0a). So the above is equivalent to
n-1 n-1
--- ---
a \ ak a0 \ ak
w z = / w + w = / w = z
--- ---
k=0 k=0
From the equation (w^a-1)z = 0, we have two possibilities.
Either w^a = 1, and then z = n. Or z = 0.