intzerotri.htm Cauchy's Integral Theorem - Proof II
Cauchy's Integral Theorem - Proof II
The fundamental result - Cauchy's Integral Theorem - says roughly:
If C is a simple closed path and w = f(z) is analytic inside and on C, then
⌠
(⎜)
⌡


C 
f(z)  dz = 0.
There are two common approaches to this result. The first approaches the Cauchy-Riemann equations and Green's Theorem. The second approach uses less assumptions about the regularity of the derivative f′ and builds up the proof by first considering C to be a simple closed triangle and then approximating the general simple closed path by a simple closed polygonal path.


Cauchy's Integral Theorem for a Triangle Using Bolzano-Weierstraß

Theorem. Let T be a simple closed triangle enclosing a region D. Suppose that on D ∪T, w = f(z) is analytic. (No assumption is made on the continuity of f′(z).) Then
⌠
(⎜)
⌡


T 
f(z)  dz = 0.
Proof: The proof is by contradiction. Suppose there is a triangle T0 for which
⎢
⎢
⌠
(⎜)
⌡


T0 
f(z)  dz⎢
⎢
= δ > 0.
Let the perimeter of T0 be p0. Using the midpoints of eachside of T0, divide T0 into four congruent triangles, each of perimeter p1 = [(p0)/(21)].

triangle.gif

On at least one of the four triangles, call it T1,
⎢
⎢
⌠
(⎜)
⌡


T1 
f(z)  dz⎢
⎢
≥ δ

41
.
Next, using the midpoints of eachside of T1, divide T1 into four congruent triangles, each of perimeter p2 = [(p0)/(22)]. On at least one of the four triangles, call it T2,
⎢
⎢
⌠
(⎜)
⌡


T2 
f(z)  dz⎢
⎢
≥ δ

42
.
Continuing in this manner, we construct a shrinking sequence of similar triangles, Tn, of perimeter pn = [(p0)/(2n)]. with
⎢
⎢
⌠
(⎜)
⌡


Tn 
f(z)  dz⎢
⎢
≥ δ

4n
.
By the Bolzano-Weierstraß Property, there is a number z0 within all the triangles. Since f(z) is analytic at z = z0, near z0,
f(z) = f(z0) + f′(z0)·(z − z0) + o(z−z0).
Thus
⌠
(⎜)
⌡


Tn 
f(z)  dz
= ⌠
(⎜)
⌡


Tn 
f(z0) + f′(z0)·(z − z0) + o(z−z0)  dz
= 0 + 0 + ⌠
(⎜)
⌡


Tn 
o(z−z0)  dz
= o⎛
⎝
1

2n
⎞
⎠
p0

2n
= o⎛
⎝
1

4n
⎞
⎠
.
But [(δ)/(4n)] is not o([1/(4n)]).


If P is a simple closed polygon, it follows that if f(z) is analytic on and inside P,
⌠
(⎜)
⌡


P 
f(z)  dz = 0.
The case of C being a simple closed oriented piecewise C1 path follows by approximating C by simple closed polygons.



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On 20 Feb 2012, 10:21.