MATH 180 FALL 1995
ASSIGNMENT #36 |
| A calculation shows that f(0.9129311) > 0 and f(0.9129300) < 0. The sign change shows that 0.9129300 < r < 0.9129311. Thus 0.913 approximates r to 2 decimal places since |0.913-r| < 0.913-0.9129300 < 1/200. |
| A calculation shows that f(3.68406) > 0 and f(3.68403) < 0. The sign change shows that 3.68403 < r < 3.68406. Thus 3.684 approximates r to 2 decimal places since |3.684-r| < 3.68406-3.684 < 1/200. |
| A calculation shows that f(0.73908) > 0 and f(0.73911) < 0. The sign change shows that 0.73908 < r < 0.73911. Thus 0.739 approximates r to 2 decimal places since |0.739-r| < 0.73911-0.739 < 1/200. |