Math 165: Income and Investment Streams
Math 165: Income and Investment Streams
Simple Model
If a present value P is invested at time t=0 with continuous compounding (CC) at rate r, the future value at time t=T is
B = B(T) = P erT = P(0) erT.
If we wish to have future value B at time t=T, we should invest a present value P given by
P = P(0) = B e−rT = B(T) e−rT.
If we wish to withdraw amounts B1, B2, …, BN, at times T1, T2, …, TN, we must have present value
P = P1 + P2 + …+ PN = B1 e−rT1 + B2 e−r T2 + …+ BN e−rTN =
Bi e−rTi.
Continuous Model - Income Stream
We wish to withdraw a continuous income stream - to withdraw continuously at a rate R [dollars/ year] for T [years].
At a typical time t, over a period ∆t, we will withdraw ≈ R ∆t = ∆B, a future value at time t. Thus we need a present value (investment) ∆P ≈ e−rt R∆t. The total present value needed is
P =
∆P ≈

t  from  0  to  T 
e−rt R∆t ≈
T

0 
R e−rt dt.
Figure 1.

strpic1.gif

Similarly, if we invest continuously at rate R [dollars/year] for T [years], the future value B at time T will be given by
B =
T

0 
R er(T−t) dt.




Figure 2.

strpic2.gif

Inflation Adjustments
Similar arguments can be made if the rate, R = R(t), depends on t. For example, the rate of contribution (investment) or income (revenue) might be continuously adjusted for inflation. In this case the formulas become:
If we wish to withdraw a continuous income stream - to withdraw continuously at a rate R(t) [dollars/ year] for T [years], we need a present value
P =
T

0 
R(t) e−r t dt.
In particular if we make a cost of living adjustment (COLA), of r1% annually,

R(t)
= R0 er1 t,
P
=
T

0 
R0 e(r1 − r)t dt
If we invest continuously at rate R(t) [dollars/year] for T [years], the future value B at time T will be given by
B =
T

0 
R(t) er(T−t) dt.



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On 18 Sep 2014, 15:43.