seriesconv.htm Power Series Convergence
Math 181 Calculus II Power Series Convergence JL

Convergence and Absolute Convergence
*CN CONVerges iff

lim
N → ∞ 
N

* 
Cn
exists (finite).
Compare to
*f(x)  dx CONVerges iff

lim
X → ∞ 

X

* 
f(x)  dx
exists (finite).
*Cn CONVerges ABSsolutely iff ∑*|Cn| converges or

lim
N → ∞ 
N

* 
|Cn|
exists (finite).
Compare to
*f(x)  dx CONVerges ABSsolutely iff ∫*|f(x)|  dx converges or

lim
X → ∞ 

X

* 
|f(x)|  dx
exists (finite).
*|Cn| converges iff the sequence ∑*N |Cn| is bounded.
*|f(x)| converges iff the function ∫*X |f(x)|  dx is bounded (as X → ∞).


Comparison Test for Absolute Convergence
If
0 ≤ An ≤ Bn,
then
0 ≤

* 
An

* 
Bn.
So that if the bigger series ∑*Bn CONVerges, the smaller series ∑*An CONVerges also.
If the smaller series ∑*An DIVerges, the bigger series ∑*An DIVerges also.
If
0 ≤ f(x) ≤ g(x),
then
0 ≤


* 
f(x)  dx ≤


* 
g(x)  dx.
So that if the bigger integral ∫*g(x)  dx CONVerges, the smaller integral ∫*f(x)  dx CONVerges also.
If the smaller integral ∫*f(x)  dx DIVerges, the bigger integral ∫*g(x)  dx DIVerges also.

Ratio Test for ABSolute CONVergence
For the series ∑*CN, suppose that

lim
n → ∞ 

Cn+1

Cn

= L.
If 0 ≤ L < 1, the series ∑*CN CONVerges ABSolutely.
If 1 < L ≤ ∞, the series ∑*CN DIVerges.
If L = 1, we are not sure - additional information is needed about DIVergence or CONVergence and/or ABS0lute CONVergence.
Power Series, Radius of Convergence, and Interval of Convergence
For a power series ∑n=0 an xn, there is a number R, 0 ≤ R ≤ ∞ for which


n=0 
an xn



CONVerges ABSolutely for |x| < R,
DIVerges for |x| > R.
The number R is called the radius of convergence of the power series. R can often be determined by the Ratio Test.
If the power series ∑n=0 an xn, converges for x = x0, then for all x, |x| < |x0| the power series CONVerges ABSolutely. Thus the radius of convergence , R,is greater than or equal |x0|.
If f(x) is represented by a convergent power series for |x| < R, then for |x| < R, its derivative is represented by the convergent series ∑n=1 n an xn−1:
If
f(x) =

n=0 
an xn, |x| < R,
then
f(x) =

n=1 
n an xn−1 =

n=0 
(n+1) an+1 xn, |x| < R,
and

x

0 
f(t)  dt =

n=0 
an

n+1
xn+1 =

n=1 
an−1

n
xn, |x| < R



File translated from TEX by TTH, version 4.03.
On 22 Feb 2012, 13:24.