Let A or A(H) denote the cross sectional area at
height H.
For Beaker X,
∆H
∆V
=
1
A
,
lim
∆V → 0
∆H
∆V
=
1
A
.
For the Ink Bottle,
∆H
∆V
≈
1
A(H)
,
lim
∆V → 0
∆H
∆V
=
1
A(H)
.
Notice that for a circular flask A = π(radius)2.
Fundamental Theorem of Calculus
Let y = f(x) be a nonnegative continuous function and
let A(x) denote area of the region
(t,y):
⎧ ⎪ ⎨
⎪ ⎩
a ≤ t ≤ x,
a ≤ y ≤ f(x).
This is the region with first coordinate between a and
x , second coordinate between the x-axis and the graph of
f .
Now the change in A(x) as x changes from x to x + ∆x,
∆A = A(x + ∆x) − A(x),
is the area of the slender region and is
∆A ≈ f(x) ·∆x;
certainly ∆A is between f(x) ·∆x and f(x + ∆x) ·∆ x. Thus if f is continuous at x,
lim
∆x → 0
∆A
∆x
= f(x).
Identifying area with the integral, this is one form of the
Fundamental Theorem of Calculus (FTC):
Theorem. If f is continuous on [a,b], then for a < x < b,
d
dx
⌠ ⌡
x
a
f(t) dt
= f(x).
File translated from
TEX
by
TTH,
version 4.04. On 22 Aug 2014, 04:37.