Definition. (p. 149) The function f is differentiable at aif
lim
h→ 0
f(a + h) − f(a)
h
= f′(a) exists.
N.B. The function f′ is a function whose
domain is the set of all numbers a such that f′(a)
exists.
The tangent line to the graph of f at (a,f(a)) is the
line through (a,f(a)) with slope f′(a). By the
point-slope form, the equation (formula) for the tangent line [to
the graph of f at (a,f(a))] is
y = Ta(x) = f(a) + f′(a) (x −a).
If f is differentiable at a, the error of the tangent
line approximation is
ϕa(x)
≡ f(x) − Ta(x),
= f(x) − (f(a) + f′(a) (x −a) ).
Note that
lim
x → a
ϕa(x)
x − a
= 0.
Theorem 1. If f is differentiable at a, then f is continuous at a.
Proof.
lim
h → 0
(f(a+h) − f(a))
=
lim
h→ 0
f(a + h) − f(a)
h
·h
= f′(a)·0
= 0.
Examples
1.
f(x) = |x|. f is continuous (at all points in its
domain).
f′(a) =
⎧ ⎪ ⎨
⎪ ⎩
1,a > 0,
−1,a < 0,
undefined,a = 0.
2.
There are functions f which are continuous everywhere, but
differentiable nowhere.
3.
For n = 1, 2, …, the power-n function ,
Powern(x) = xn, is differentiable (everywhere) and
Powern′(x) = n xn −1.
4.
We will assume that the trigonometric functions, sin
and cos, are differentiable and
sin′(x)
= cos(x),
cos′(x)
= − sin(x).
5.
Let
f(x) =
⎧ ⎪ ⎨
⎪ ⎩
x sin(1/x),x ≠ 0,
0,x = 0.
Then f is continuous at 0, but not differentiable at 0. The
difference quotient at 0 is
f(0 + h) − f(0)
h
=
h sin(1/h)
h
= sin(1/h),
which does not have a limit as h → 0.
6.
Let
f(x) =
⎧ ⎪ ⎨
⎪ ⎩
x2 sin(1/x),x ≠ 0,
0,x = 0.
Then f is continuous at 0, and differentiable at 0. The
difference quotient at 0 is
f(0 + h) − f(0)
h
=
h2 sin(1/h)
h
= h sin(1/h)
→ 0 ash → 0.
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